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Problem Description
Many years ago , in Teddy’s hometown there was a man who was called “Bone Collector”. This man like to collect varies of bones , such as dog’s , cow’s , also he went to the grave … The bone collector had a big bag with a volume of V ,and along his trip of collecting there are a lot of bones , obviously , different bone has different value and different volume, now given the each bone’s value along his trip , can you calculate out the maximum of the total value the bone collector can get ?
Input
The first line contain a integer T , the number of cases. Followed by T cases , each case three lines , the first line contain two integer N , V, (N <= 1000 , V <= 1000 )representing the number of bones and the volume of his bag. And the second line contain N integers representing the value of each bone. The third line contain N integers representing the volume of each bone.
Output
One integer per line representing the maximum of the total value (this number will be less than 231).
Sample Input
1 5 10 1 2 3 4 5 5 4 3 2 1
Sample Output
14
题意: 第一行输入例子的组数,然后接着三行 第二行分别输入N,V代表骨头的数量和包的容量 第三行输入每个骨头的价值 第四行输入每个骨头的容量
#include#include #include using namespace std;//HDU2602Bone Collectorint main(){ int z,N,V; int i,j; int f[100]={ 0}; int vg[100]={ 0}; int rg[100]={ 0}; while(scanf("%d",&z)!=EOF){ //输入组数 scanf("%d%d",&N,&V); //再依次输入骨头价值和容量 for(i=0;i =rg[i];j--)//逆序表达 f[j]=max(f[j],f[j-rg[i]]+vg[i]); printf("%d\n",f[V]); }}
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